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assignment A1 fall 2018 Page 1
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About the Download

12/6/2018

A1Solutions

AP/ITEC1000 Sections A and B “Introduction to Information Technologies”

Fall 2018

Assignment # 1

Answers and Solutions

1.a 371910 = 1110100001112 because

3719 / 2 = 1859 remainder 1 1859 / 2 = 929 remainder 1 929 / 2 = 464 remainder 1
464 / 2 = 232 remainder 0 232 / 2 = 116 remainder 0 116 / 2 = 58 remainder 0 58 / 2 = 29 remainder 0 29 / 2 = 14 remainder 1 14 / 2 = 7 remainder 0
7 / 2 = 3 remainder 1 3 / 2 = 1 remainder 1 1 / 2 = 0 remainder 1

1.b 333.2510 = 101001101.012 because

333 / 2 = 166 remainder 1 166 / 2 = 83 remainder 0 83 / 2 = 41 remainder 1 41 / 2 = 20 remainder 1 20 / 2 = 10 remainder 0 10 / 2 = 5 remainder 0 5/ 2 = 2 remainder 1 2 / 2 = 1 remainder 0 1 / 2 = 0 remainder 1

And

0.25 x2
0.50 x2 ——–
1.00

1.c 0.8462910 = 0.11011.. 2 because

0.84629 x2 1.69258 x2 1.38516 x2 0.77032

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